# Line slope calculator 2x+3y=16

**Straight line given by points A[2; 4] and B[5; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.6667x+5.3333

**Canonical form of the line equation:**2x+3y-16 = 0

**Parametric form of the line equation:**

x = 3t+2

y = -2t+4 ; t ∈ R

**Slope:**m = -0.6667

**Slope angle of line: φ =**-33°41'24″ = -0.588 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 5.3333

**Distance line from the origin:**d

_{0}= 4.4376

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; -2)

**Normal vector: n =**(2; 3)

**Midpoint of the segment AB: M =**[3.5; 3]

**Perpendicular Bisector equation:**3x-2y-4.5 = 0

**Vector OA = (2; 4) ; |OA| = 4.4721**

**Vector OB = (5; 2) ; |OB| = 5.3852**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 41°38'1″ = 0.7266 rad**